How to Watch Underworld Movies in Order?
It's been almost two decades since Kate Beckinsale took on the role of Selene in Underworld. Even now, years later, the story and the movies are nice to watch for anyone looking for a clash between vampires and werewolves.
The Underworld series wasn't necessarily the biggest franchise of its time, but it did draw in tons of viewers.
Who Plays in Underworld?
The Underworld movies feature a ton of cool actors, including Kate Beckinsale, Bill Nighy, Michael Sheen, Scott Speedman, Shane Brolly, and many others.
How to Watch Underworld in Release Order?
Obviously, one of the easiest ways to watch Underworld is by the movie's release order, like everyone else got to experience the series at the time.
- Underworld (2003)
- Underworld: Evolution (2006)
- Underworld: Rise of the Lycans (2009)
- Underworld: Endless War (2011)
- Underworld: Awakening (2012)
- Underworld: Blood Wars (2016)
How to Watch Underworld in Chronological Order?
If you want to view the movies in chronological order, you're going to have to make a few changes because there's a timeline jump right in the middle of the series. Therefore, you'll need to watch Rise of the Lycans first like so:
- Underworld: Rise of the Lycans (2009)
- Underworld (2003)
- Underworld: Evolution (2006)
- Underworld: Endless War (2011)
- Underworld: Awakening (2012)
- Underworld: Blood Wars (2016)
Where to Stream Underworld Movies?
Streaming Underworld movies isn't necessarily that difficult. Even if the titles are missing right now, they'll pop up eventually.Â
- Underworld (2003) - Philo, fuboTV, AMC Premiere, AMC
- Underworld: Evolution (2006) - Philo, fuboTV, AMC Premiere, AMC
- Underworld: Rise of the Lycans (2009) - Philo, fuboTV, AMC Premiere, AMC
- Underworld: Endless War (2011) - not available for streamingÂ
- Underworld: Awakening (2012) - Philo, fuboTV, AMC Premiere, AMC
- Underworld: Blood Wars (2016) - Philo, fuboTV, AMC Premiere, AMC
Keep in mind that licensing deals can expire and the movies can end up on a different service altogether.